Problem 1 Project Euler solution with python

Multiples of 3 and 5

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

File: pep1.py ------------- #http://radiusofcircle.blogspot.com #Time module for counting time import time #Time at the start of the program start_time = time.time() #For loop for sum less than 10 #To check if we are correct #sum1 variable to store the value of sum less than 10 sum1 = 0 #A for loop to iterate through numbers 1 - 10 for i in range(1,10): if i%3 == 0 or i%5 == 0: sum1 = sum1+i #Printing the result with .format() print 'Sum of Natural Numbers less than 10' print 'That are divisible by 3 or 5 is {}\n'.format(sum1) #For loop for sum less than 1000 #sum2 variable to store the value of sum less than 1000 sum2 = 0 #A for loop to iterate through numbers 1 - 1000 for i in range(1,1000): if i%3 == 0 or i%5 == 0: sum2 = sum2+i #Printing the result with % print "Sum of Natural Numbers less than 1000" print 'That are divisible by 3 or 5 is %d\n'%sum2 #Time at the end of program end_time = time.time() #Total time total_time = end_time - start_time #Printing the total time taken print 'Total time taken for running is {}'.format(total_time)

First I have written my program for number up to 10. This ensures me that if anything goes wrong at this stage I can sort it out.

Also I have commented each and every part of the program which makes it easy even for beginners to understand the program.

I think at this stage you might want to know about the string formatting using % and .format for which you can see Basic Formatting on PyFormat

If you want you can download the file from Github

Output

If you have any doubt or didn't understand any part of the code then comment in the comment box below and I will be glad to help you. You can also contact me if you want.

See Solution to Project Euler Problem 2 with python

Problem 60 Project Euler Solution with python

Prime pair sets The primes 3, 7, 109, and 673, are quite remarkable. By taking any two primes and concatenating them in any order the result will always be prime. For example, taking 7 and 109, both 7109 and 1097 are prime. The sum of these four primes, 792, represents the lowest sum for a set of four primes with this property. Find the lowest sum for a set of five primes for which any two primes concatenate to produce another prime. This problem is j u st a brute force problem. If you have come here because you don't know the limit upto which you will h ave to gener ate the prime numbers t hen go ahe ad and t r y with 10,000 . When I first start ed solving the problem I chose 1 million(beca use most of the problem s on project E uler have this limit ), but it took very long for the computer to fin d the solution. After searching on the internet then I found many people choosing 10, 000 so I have changed my in put f rom 1 million to 10000 and the output was f ast. He

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RADIUS OF CIRCLE

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