Skip to main content

Problem 7 Project euler solution with python

10001st prime

By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13.
What is the 10 001st prime number?

Even though this problem is easy as it looks, it took me 1 day to find a better solution for this problem. I have started writing solution for this program yesterday. I have searched on internet a lot about prime numbers to find the perfect solution.

The first solution which gave me inspiration was this one: Jason Martin's answer to What are good ways to find nth prime number in the fastest way? - Quora 

While answer by Jason Martin was pretty straight forward, I first thought that there would only be one prime in the range given by nln(n)+n(ln(ln(n))-1) < nth prime < nln(n)+nln(ln(n)). But what I later discovered was that my assumption was false and simply using the above formula was of no use.

As there was no formula for generating nth prime easily, my next option was to check if the given number is prime or not. And after I have written the function for Primality test, I will have to loop through each and every number till I have reached the 10001 prime.

This was the start for my solution(first program). I found this page on wiki which was really useful and I have learned a lot.- Primality test - Wikipedia, the free encyclopedia.

Accordingly there are few conditions for checking if the number is prime or not. They are as follows.(Let us assume the number is n)
  1. (n+1) or (n-1) should be evenly divisible by 6. i.e. (n+1)%6 == 0 or (n-1)%6 == 0
  2. A prime number will be divisible by a number less than its square root.
While most of the numbers got eliminated during the first condition, a few of them survived. All the composite numbers were eliminated during the second condition.

Using the first condition have saved a lot of time.

Okay no more confusion, I will show you the first program I have written:

#http://radiusofcircle.blogspot.com

#import time and math modules
import time, math

#Time at the start of execution
start = time.time()

#Function to check if the number is prime or not
def isPrime(n):
 if (n+1)%6 == 0 or (n-1)%6 == 0:
  for i in range(2, int(round(math.sqrt(n)+1))):
   if n%i == 0:
    return False
  return True
 return False

#Counter for counting the prime numbers
#We took it equal to 2 because
#we are starting with 4 and have already counted 2,3
counter = 2

#Numbers starting from 4
i = 4

#Assuming the nth-prime to be 0
prime = 0

#Starting a for loop
while counter < 10001:
 if isPrime(i):
  counter = counter+1
  prime = i
  i = i+1
 i = i+1

#Printing the output
print str(counter)+' prime is '+str(prime)

#Time at the end of execution
end = time.time()

#Printing the time of execution
print end-start
I think this program is pretty simple to understand, also I have added comments to this program so that it will be easy for everyone to understand.
You may be confused on why I have used counter=2 and i=4.
See we know that the prime numbers are 2,3,5,7...
when I have started iterating from 4,that means I have left 2 prime numbers already and so the counter which counts the prime number's rank is 2

Even though this program was efficient and had an execution time of almost 0.217seconds, I was not satisfied and wanted a faster program and so is the next program I will present it with you.

This program uses the concept of Sieve of Erotosthenes. And for writing the program you can see Sieve of Erotosthenes The python way and Finding Prime Numbers. The use of Sieve of Erotosthenes was suggested by Charles.

Program

Okay the program is as follows:
I am assuming that you have read about the sieve of Erotosthenes atleast from one of the links above and so I am not explaining the program.
But if you still have not understood the sieve concept then I would suggest you to take an example value(Don't take very large values) and start iterating manually, I am sure that you will understand the concept easily.If not comment below.
If you want to download the file you can download it from github gist

Output

Summary

Before solving this problem I didn't even have any idea about the tests with which we can find whether the given number is prime or not. After solving this problem now I know atleast few properties of prime numbers, primality tests etc. I am happy that I have written a program which has a good execution time using the sieve of Erotosthenes.

Eventhough I have written a program which had small execution time, there might be still better program with you which even has little execution time. I would be glad if you can share your code with me and this community.

I have not explained any code in this post because, to understand these programs you need to know some other concepts for which I have linked to. Even after reading if you are have any doubt or didn't understand anything then please do comment in the comment box below and I will be glad to help you.

Please don't hesitate to comment in the comment box if I have made any typo or have missed any description.

You can also contact me if you want to.

Thank you. Have a nice day☺️.

Popular posts from this blog

Project Euler Problem 67 Solution with Python

Maximum path sum II By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23. 3 7 4 2 4 6 8 5 9 3 That is, 3 + 7 + 4 + 9 = 23. Find the maximum total from top to bottom in triangle.txt (right click and 'Save Link/Target As...'), a 15K text file containing a triangle with one-hundred rows.

Problem 43 Project Euler Solution with python

Sub-string divisibility The number, 1406357289, is a 0 to 9 pandigital number because it is made up of each of the digits 0 to 9 in some order, but it also has a rather interesting sub-string divisibility property. Let d 1 be the 1 st digit, d 2 be the 2 nd digit, and so on. In this way, we note the following: d 2 d 3 d 4 =406 is divisible by 2 d 3 d 4 d 5 =063 is divisible by 3 d 4 d 5 d 6 =635 is divisible by 5 d 5 d 6 d 7 =357 is divisible by 7 d 6 d 7 d 8 =572 is divisible by 11 d 7 d 8 d 9 =728 is divisible by 13 d 8 d 9 d 10 =289 is divisible by 17 Find the sum of all 0 to 9 pandigital numbers with this property. One might write a simple solution using direct if else statements for this problem. Using if else statements, the execution time may be a few seconds. But this is not a very good approach. I too had written a program with if else statement which will take each and every permutation of the 0-9 Pandigital and check for the conditions given in the qu...

Add/Embed SVG to Blogger website

In this post I will tell you my method(trick) of adding SVG images in a blogger website or blog. Before starting , the first thin g I am assu m ing is that you are aware of SVG if you are here. If not please see S calable V ec tor G raphics Recently when I tried to embed a SVG image for a post on pygal, I tried uploading the SVG file and blogger Image uploader came up with an error, because of which I had to find some other way.  SVG File upload Error in Blogger  I started sea rc hing Google " Embed SVG in Blogger " . I found blogorrhea , w h ich gave some i nformatio n on add ing SVG directly as a markup , which worked , but I faced another problem using this . Also th is guy has used lot of Javascript which was confusin g for me, being new to using SVG.   So I first t houg ht of learning on h ow to embed SVG in HTML and t his on e worked out. Actually we can embed SVG in HTML i n following ways: Using Object tag Using Iframe tag Using embed...