Skip to main content

Problem 29 Project Euler Solution with python

Distinct powers

Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:

22=4, 23=8, 24=16, 25=32
32=9, 33=27, 34=81, 35=243
42=16, 43=64, 44=256, 45=1024
52=25, 53=125, 54=625, 55=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:

4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?

This problem doesn't require a lot of background work, just a bit of basics in python can solve this problem. I think you should read the following two articles before seeing the program. They are optional of course.

I think there is no need for any algorithm because we just have used a very direct and basic solution.

Program 

In this program we have used sets at the end even though sets are unordered lists because we are not actually concerned about the order in which the numbers are arranged but we are concerned about the length of the iterable. You can arrange the order if you want to. The solution will be the same even if you will arrange the order or not.
 
You might be wondering with a few questions after seeing the program. 

Why did I use lists instead I could have just used sets?
When I tried sets, instead of lists I found that there was no considerable improvement in the performance, may be because we are just looping for small range. I have sticked myself to lists so that the code is readable and easy to understand for each and everyone.

Why did I use append instead of extend?
When I tried extend instead of append I found that the execution time increased. This might be because of converting each and iterable to a list to add it. I am not sure why, but you can tell it to me if you know why. 

Why did I use '**' instead of using pow()?
Again I have seen same execution time for both of these methods and I have sticked myself to using the more familiar '**' instead of pow().

Guys I am writing what I have seen on my computer. This might not be the case on your computer. I suggest you check these on your computer and you can comment your experience in the comment box below. Please do include the reason in the comment if you know.

Discussions are welcome.

You can download the source code from Github Gist pep29.py

Output


Summary

I am not bothered about the performance of the program because it is running under 1/50 of a second. Also it didn't take a lot of time for me to solve this problem. This may be because of using python for programming the solution, which already has a lot of in-built tools for over coming some of the common problems. 

If you have any doubt or didn't understand anything then feel free to comment in the comment box below and I will be glad to help you as soon as possible.

Please feel free to comment if you have found any typo or have a better solution or a different program or any suggestion. 

You can also contact me.

Thank you. Have a nice day😃.

Popular posts from this blog

Project Euler Problem 67 Solution with Python

Maximum path sum II By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23. 3 7 4 2 4 6 8 5 9 3 That is, 3 + 7 + 4 + 9 = 23. Find the maximum total from top to bottom in triangle.txt (right click and 'Save Link/Target As...'), a 15K text file containing a triangle with one-hundred rows.

Problem 43 Project Euler Solution with python

Sub-string divisibility The number, 1406357289, is a 0 to 9 pandigital number because it is made up of each of the digits 0 to 9 in some order, but it also has a rather interesting sub-string divisibility property. Let d 1 be the 1 st digit, d 2 be the 2 nd digit, and so on. In this way, we note the following: d 2 d 3 d 4 =406 is divisible by 2 d 3 d 4 d 5 =063 is divisible by 3 d 4 d 5 d 6 =635 is divisible by 5 d 5 d 6 d 7 =357 is divisible by 7 d 6 d 7 d 8 =572 is divisible by 11 d 7 d 8 d 9 =728 is divisible by 13 d 8 d 9 d 10 =289 is divisible by 17 Find the sum of all 0 to 9 pandigital numbers with this property. One might write a simple solution using direct if else statements for this problem. Using if else statements, the execution time may be a few seconds. But this is not a very good approach. I too had written a program with if else statement which will take each and every permutation of the 0-9 Pandigital and check for the conditions given in the qu...

Add/Embed SVG to Blogger website

In this post I will tell you my method(trick) of adding SVG images in a blogger website or blog. Before starting , the first thin g I am assu m ing is that you are aware of SVG if you are here. If not please see S calable V ec tor G raphics Recently when I tried to embed a SVG image for a post on pygal, I tried uploading the SVG file and blogger Image uploader came up with an error, because of which I had to find some other way.  SVG File upload Error in Blogger  I started sea rc hing Google " Embed SVG in Blogger " . I found blogorrhea , w h ich gave some i nformatio n on add ing SVG directly as a markup , which worked , but I faced another problem using this . Also th is guy has used lot of Javascript which was confusin g for me, being new to using SVG.   So I first t houg ht of learning on h ow to embed SVG in HTML and t his on e worked out. Actually we can embed SVG in HTML i n following ways: Using Object tag Using Iframe tag Using embed...