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Problem 40 Project Euler Solution with python

Champernowne's constant

An irrational decimal fraction is created by concatenating the positive integers:
0.123456789101112131415161718192021...
It can be seen that the 12th digit of the fractional part is 1.
If dn represents the nth digit of the fractional part, find the value of the following expression.
d1 × d10 × d100 × d1000 × d10000 × d100000 × d1000000
This problem requires a small homework to set the upper limit for the for loop. This is general mathematics.

We have 9, 1 digit numbers
90, 2 digit numbers
900, 3 digit numbers
9000, 4 digit numbers
90000, 5 digit numbers
900000, 6 digit numbers

Which will total to 5888889 digits. But we only need 1000000, so that
9 x 1 digit
90 x 2 digit
900 x 3 digit
9000 x 4 digit
90000 x 5 digit
n x 6 digit

= 9*1 + 90*2 + 900*3+ 9000*4 + 90000*5 + n*6 = 1000000
So the value of n is approximately 85186 that means that we will have to do iterations until 185186.

The same thing has been used in the program directly.

Program

# http://radiusofcircle.blogspot.com
# time module for calculating execution time
import time
# time at the start of program execution
start = time.time()
# variable to store the values
a = ''
# for loop
for i in xrange(1, 185186):
a += str(i)
# d1
d1 = int(a[0])
# d10
d10 = int(a[9])
# d100
d100 = int(a[99])
# d1000
d1000 = int(a[999])
# d10000
d10000 = int(a[9999])
# d100000
d100000 = int(a[99999])
# d1000000
d1000000 = int(a[999999])
# printing the solution
print d1*d10*d100*d1000*d10000*d100000*d1000000
# time at the end of program execution
end = time.time()
# total time for execution
print end - start
view raw pep40.py hosted with ❤ by GitHub
Remember that the strings are indexed from 0 on wards.

As always you can download the source code from Github Gist pep40.py

This solution also satisfies PEP8 standard.

Output


Summary

I don't really have any big comments on this problem. But this problem demanded some homework and usage of basic mathematics to make it optimized and work faster. Performance wise I am satisfied and I have not tried optimizing the code. The code I have presented to you is the first draft. You can write a better code and share it with me, if possible.

As always if you have any doubt or didn't understand anything then you can comment in the comment box below, I will be glad to help you.

Please do comment if you have found any typo or have any better program or have a different program or have any suggestion. I will be glad to view each of them.

You can also contact me.

Thank you, have a nice day😃.

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