Convergents of e ¶ The square root of 2 can be written as an infinite continued fraction. $$ \begin{equation} \sqrt{2} = 1 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2....} } } } \end{equation} $$ The infinite continued fraction can be written, $ \sqrt{2} = [1;(2)]$, (2) indicates that 2 repeats ad infinitum. In a similar way, $\sqrt{23} = [4;(1,3,1,8)]$. It turns out that the sequence of partial values of continued fractions for square roots provide the best rational approximations. Let us consider the convergents for $\sqrt{2}$. \begin{equation} 1 + \cfrac{1}{2} = \cfrac{3}{2}\end{equation} \begin{equation} 1 + \cfrac{1}{2 + \cfrac{1}{2}} = \cfrac{7}{5} \end{equation} \begin{equation} 1 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2} } } = \cfrac{17}{12} \end{equation} \begin{equation} \sqrt{2} = 1 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2} } } } = \cfrac{41}{2...
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